Đề thi thử THPT QG môn: Toán - Mã đề thi 138

ri rru rstl rHPT QUoc cIA LAN I
Ndm hsc 2016-2017; Mdn: Todn
Thdi gian tdm bdi 90 phtit, khong ke thdi gian giao d€
Hg va ten thi sinh:......... ........ Phong thi: SBD:
Ciu l: Hdm s6 y = 3.rr + 2 dong bit5n tr€n khoang nAo sau ddy?
so GrAo DUC VA DAO TAO
TiNTJ BA zuA Wn rc rAU
DE CHINH TITUC
.^) ) ^,(E€ g6m 06 trang)
Me d6 138
Ciu 2z Gi6 tri cuc ti6ti yr., gitahdm s6 ! = x3 - 3x2 + 1 ld
A. yr., =7. B. lcr--3. C,yrr=0. D. yr, =2.
Ciu 3: Cho hdm sO y = /(x) lien tuc tr€n l-t;:] vd c6 bdng bi6n thi€n
Khing dinh ndo sau ddy ld khing dinh dring?
A. Gi6 tri nho nhAt cua hdm sO tr6n [-t;:] bing -2.
B. Gie tri nho nh6t cira hdm so tren [-i;3] bing -i.
C. Gi6 tri lon nhAt cua hdm so tr6n [-1;3] bing :.
D. Gi6 tri nho nhAt cira ham s6 tr€n [-1;3] bang 2.
Cf,u 4: Eo thihdm sd y =+ co ducrng tiqm cin ngang ldr
x+l
A.y=-I. B.y=2. C,x=-1. D.x=2.
ciu5: 56 giao di6m cuaduorrg thing (a)ty:x*1 vddrrongcong y=xr+l ld
A.0. B. 1. c.2. D.3.
Ciu 6: Goi M, m I|,nluort ld gitttrllo'n rilr6t vd gia tri nh6 nhit cua ham sd -f (r) = xtl2lnx-3) trOn doan
f. r-l ,,,J| 1; e' l. Khdng dinh ndo sau ddy dring?
A.(0,+*) . e. [--,-?')\ 3) c. 
( 
-?,**') .\' 3' ) D. (-..o;0).
D. M +m=-3-e2A. M+n't=eo 
-3. B. M+n1=eo -e'. C. M+m=eo.
Cdu 7: Duong cong 6 hinh b6n (Hinh 1) le do thi cua
mQt hdm sd trong bdn hdm sO duoc liqt kd trong bon
phuong 6n A, B, C, D du6i dAy. H6i d6 Id hdm sd ndo ?
L. y=-x' +3x+2. B. ! = x3 +3x+2'
C,y=x3 
-3x+2. D. y=-x3 -3x+2.
( Flinb 1)
1lM5de138
cAu 8: tAt ca cfrc gtittri cua tham s0 rr d€ ham sd y = x' - mxt + 3'r + i ddng bi6n tron R' ld
A. 
-3 3. D. m<-3.
Ciu 9: Cho ham s6 y = /(r) co dao ham cAp hai tren (a: b) vd xo e(a;b) . Kh*g dfnh nao sau day lii
rr.lKnang olnn oung r
. ,,i 
-,/ \ n , .t't \ ^A. NCu 
.f '(ro)= 0 uu /"(.to)> 0 thi "ro lir di6m cuc rieu cua hirm s6.
B. Neu ham so dat cuc tieu tai diem -ro thi /'(.ro)= O vd. f ' (.to)t O.
^ --.4 -,/ , ^,,/ \ ^C.Neu 
.f,(to)=0 uu /"(_.0)<0 thi _ro iirdi€mcuctieucuahdms6.
D.Ndu xo ld.di€mcuctri ctahdms6thi f'(*o)=0 va f"(ro)*0.
Ciu 10: Gi6 tri cira bi6u thuc A = 3J1-t .9u5 .,7'-tr bane
c" 27. D. 81.
116s
th6a mdn aa < as ; iogr -1< logr: . Khdng dinh ndo sau dAy)4
A'.3. 8.9.
Ciu 11: Cho a, b ld hai sd thuc ducrng khdc 1
ld ttfng?
A. a >l;b >1.
Cflu 12: Cho 1og, * =L
3A-n. 
-.4
Ciu 13: Bi0u thuc O =
5
A' Q=oi '
CAu 14: Cho log, 3: a,
4.. 6a + 4b.
^3uA. l/ 
--
4
'7
C' Q=n1 '
logu 67 5 theo a vd b lit
c. n+1u.
2
D. a>l;O<b <1.
AD.- 1a1J
3
D. 
-a+b.I
B. 01. C. 0<a<\A<b<I.
. Khi d6 gi6 tri bi6u rhuc o = 
to*'it":)-tot' ; oin,
x-+1og6x
s-l
4
1)r
11IJ
8
D' a= n'
(r)'y=l-l
\a)
^n-r1 f/\,, y =-
A+
oo .1,[7 Qoi a > 0; a + 1). Ding thu'c ndro sau ddy thing?
:
B'Q=at 
'
, 
^.1 1.:logr ) :0. IJleu Olen
B.4a+6b.
Cf,u 15: Cho a > 0,a + 1 . M€nh dO ndo sau dAy thing?
:"A. HAm s6 y: a'' vai a > 1 nghich bi€n trdn tdp R .
B. Hdm s6 y = a' voi 0 < a <1 d6ng bi6n trdn t4p R .
^ ^^... A , (t).. ^ JC. D0 thi hai hdm so | = a';y =l 
- 
| ludn nam phia tr€n truc hodnh.
- \a )
D. EO thi hdm s6 y: a' nim phia tr6n truc hodnh vd d6 thi hdm s6
hodnh.
nim phia du6i tryc
Ciu 16: Cho hinh chop S.lB C co ddy lir tam gi6c dAu canh bing a , canh bdn Sl r.'udng g6c vdi mp(ABC)
vd Sl = oJ3. th6 tich cua kh6i chop S.ABC lit
B.V=a3 D.V=
2lMdde 138
Ciu 17: Cho hinh hQp drmg ABCD.A',7'C'D' c6 dfy ABCD 1e hinh thoi canh bing a, goc A=60" vdr
canh bdn AA' = 2a . Tltt th€ tich cua khOi hQp ABCD.I ts'CD' lat
--"-
.l /r n3 l'tA.v=,'vJ. B.v="ut62
Ciu 18: Khing dinh ndo sau dAy sai?
A. The tich cria khdi cau c6 ban kinh R lit V =lrRt .
3
B. Di0n tich cira mdt cAu co bdn kinh R ld S = 2n R2 .
C. The tich cua khdi trp c6 ban kinh d6y R vd chidu cao h ld V = nR2h.
D. The tich cua khOi nOn co b6n kinh d6y R vd chiAu cao h Lit V =! ontl, .
3
Ciu 19: fhitSt aien qua truc cira mdt hinh trp ld mQt hinh r.u6ng c6 chu vr 8a. Diqn tich xung quanh cira
hinh tru d6 ld
o. s.,r =2fia2. B. srr=4a2. c. s,o : 4ra2 . P. S.n =8naz '
Ciu 20: Cho kh6i n6n c6 b6n kinh ddy R = a, ducrng sinh tao v6i mdt ddy mQt goc 45" . th0 tich cua kl6i
n6n ld
nn3 nl
B. V ='""" . g. 1l =i_ .
C. V = or .E . D. V =zat Ji .
nn3
D. V =""'
o
Ciu 21: Trong kh6ng gian vdi h6 truc tqa dQ Oryt, cho tri di€n ABCD c6 l(1;0;0); 8(0;1;1);
C (2;l;0) ; D(0 ;f 3) . thd tich cira kh6i ru diqn ABCD lit
A.V=4. B.V=!. C.V:L. D.V=?.333
Ciu 22: Trong kh6ng gian v6i hQ truc tqa dQ Oryt , cho tam gi6c ABC co A(l;2;l); B (IJ;0) ; C (\;0;2) .
Kho6Lng c6ch til trong tdm tam gi6c ABC d€ntrung di6m c4nh lB bang
.l; ^t; )^1,A.d=at B.d=a' C.cl=2. D.c{=L\L223
Ciu 23: Gi6 tri lcm nhAt cira hirm sO y = * - Jt- f n
A. -1. B. 
-Jt. c. i. D. J'
Ciu Z4zGei (C) ld dd thi cLia hdrm sO y = 4 
"U ,4.1 Id mQt 
di6m thuQc (C) cO tung dO bingl. Tqa dd
r-t
cua di€m M lir
. /^ ^\A. I J:Zl.l n. (z;z). c. (:;t).
Ciu 25: t6t ca cdc grit tri cua tham sd rr dd phucrng trinh x3 +3x' 
-2 = m c6 ba nghiQm thuc phAn biQt ld
I m>2A. l B.-2<m<2. C.-2<m<0.
Lm <-/
CAu 26: Cho (C) ld do rH cria hirm sd y=.v'-3r' +4x+2 vd (l) ld tiep ruy6n cua (C) c6 hQ s6 g6c
, i. 
-nh6 nhat. Trong cdc di€m sau dAy di€m ndo thu0c (A) ?
A. M (o;:). n. I'r(-t;:). c. r(:;o) ,
D. (o;2) .
D.0<nt<2.
n. Q(o;z).
Cdu27: Gi6 triciratham s6 m d€him so !: x3 _ 3x2 + mx- | co hai di6m cgc trixl,x2thoa xf +x2, =6 1i
A. 
-1. 8.3. c. 1. D. -3.
3 lMa ae t:s
Cdu 28: T4p x6c dinh cua ham s6 y :Iog(2t -:x'?) ta
(t \ f r\ (z \ (z\
A. (--;o)rl1;+- l. B. l--'-; lr(0;+*). c I-:;o l' D' | 0:: l'\) / \ r,, - ( 3' ) \'3)
Cdu 29: Dao h2rm cua ham s6 y =ln(.rt +3) la
1 "- )yln) )YA. t,'= --;----.. 8 . ," ='^' ./ 
x2 +3' x, +3' ' x. +3 (.r, +3)ln2
ciu 30: T4p x6c dinh cua hdm s6 y =logt (r+2016)+x-'0" ie
A. (-2016;+.o). n. (-zorc;+-)r{o}. C. (0;+-). D.(-201610)'
Ciu 31: Phuorg trinh ln (Zx +1) = I c6 nghiQm
^ e+l B. *='-r. c. *=2. n.t=T.A. )f =-.2' 2' 2 2
Ciu 32: Tdp nghidm phucrng trinh 3r' -23'*t -27 =0 lit
A.s={2)}. B.s={z;-t\. c.s={2}. D.s=a'
Ciu 33: T6ng binh phucrng c6c nghi€m cira phuong trinh log, x + 1og, x =I+log' x'log, x bing
A.2. 8.5. c' 13. D.25.
Ciu 34: B6t phuong trinh log,, x > log, (x + f ) tuo'ng ducrng voi bAt phuong trinh niro sau dAy?
,)J
A. logo r > 1og, x+log, 1. B. 2log' x > logr (x+1).
-13q33
C. log, x > logo (x+1). D. 1og, x>2logr(x+1).
1'll
7.
Cf;u 35: BAt phucrng trinh (Jt)'-*' u 2'*o c6 tAp nghiQm ld
A. R\(-r;g) B ft\[-t;:]. c. [-t;:]. D. R.
Ciu 36: V6i gi6 tri ndo cua mthi b6t phucrng trinh 1+ log, (r' -Z** + m= -2n + a)> lo8z (x' +Z) nghiQm
dirng v6i Vx e R, 
, m <_3
A. m 1. C. -3 <m <1. D'l 
*rt
cAu 37: Cho hinh chop s.ABCD co day ABCD ld mdt hinh thoi, AC = 4a , BD = 2a . MAt ch6o SBD ndm
trong m6t phing vu6ng g6c vdi mat phing (ABCD) vd SB = nJj; SD = a . ThO tich cira t<troi chop
S.ABCD lir
A.. v =9otJi. B ., =4nt,6. c. , ='ot^&. D . v =2at'l-3 .333
Ciu 38: Cho hinh ch6p dpu S.ABCD co canh d6y bing 2a,\<hodng tu tdm cia diry ABCD d€n mflt bOn
t;
, t/1r1,/ 
"bang T. The tich cua kh6i chop S.ABCD IiI/.
n3 ? o3 4atA.v=L. B.V="u C.V=-. D.V=4a3.3' 3 3
4 lMa Aa rss
Ciu 40: Cho kh6i ch6p S.,4BC c6 mdt b6n S,4B Id m6t tam gi6c ddu canh AB =2a. Gqi M lir trung di6m
cua canh BC. ThC tich cria m6i chOp S.tWB bdng c3..6. fhoattg cdch tu diOm C d6n mflt phdng 6A8)
tinh theo a ld
A. d =24a . B. d =1.2a. C. d =8a. D. d=6a.
CAu 41: MQt hinh ch6p ru gi6c ddu c6 dinh trung v6i dinh cua m6t hinh n6n vdL c6c dinh con 14i cua d6y
I 
^ 
+, r 1 \ 1 , A ' t, 
't'hinh ch6p ndm trdn duong tron d6y cua hinh n6n. Goi V, th€ tich kh6i ch6p tir gidc ddu, Vz ldthe tich cira
khdi n6n trdn thi ti s6 k - 
o" 
ld"
T/r)
C. k=2. D. k=6.
Ciu 42: Cho m6t chi6c bO hinh trp chfa dAy nudc. Nguoi ta bo vdo ddy ba quA cAu sit ddc, c6 cirng b6n
kinh vd do duoc lu-o. ng nu6c tran ra ngodi bd c6 th€ tfch ld 4tt.,bi€tring duong trdn d.6y ctra hinh trp bdng
ducrng tron lcm 
"uu 
q.,a cAu. Ducrng sinh cua hinh tru g6p ba lAn duong kinh cua quA cAu. Th€ tich cira kh6i
tru ld
A.V=3n. B.V=6tr. C. V =12n. D. V =24tr .
Ciu 43: Trong kh6ng gian voi h0 truc toa dQ Ory, , cho A(1;1;1) ;B(2;\;-\); C (0;a;6) . Di6m M di
ddng tr6n truc hodnh Ox . ToadQ di6m M de P =IMA+ Un * MCI dat gi|tri nh6 ntrAt taII
A. M(r;2;2). B.M(1;0;0). C.M(0;I;0). D.M(-1;0;0).
: .. ^ oJ6 ,.;Ciu 44:Cho hinh cdu bdn kinh R :; ngoai ti€p mQt hinh ch6p tri gi6c d€u c6 chidu cao t =o& .ft e
, 11;. | 
'tich cria khdi chop tri gi6c ddu ld
A.V=otJ6.
Cdu 45: pO tn hdm sd ! = xa -2mx2 + m+I c6 ba di€m cuc tri tao thdnh m6t tam
32 k}li
A. m=li. B, m=1. C. m=2.
Ciu 46: TAt cd cdc grit tri cua m sao cho dd thi hdm s6 y =
A. m=0
'- ^\, ,Cdu 47 z Tdt cd ctrc gi6 tri cria
11A.-.-1717 1 
-.,12 
^!2
11L. 
---F <171 < 
-.11 11\IL \L
Cdu 39: Cho hlnh hQp chlr nhat c6 duong chdo d : n^127 vd dQ ddi ba kich
;. i.
cdp s6 nhAn v6i cong bQi Q:2 . The tich cua kh6i hQp chir nhat ie
B.V=6a3. C.V=4nt
aJ
^1A. V =Ea'
thu6c cira n6 16p thanh mdt
9,n3
D. V ="*
3
B. k:!.
2
1A. k:-.
6
B. v =nt J6
2
m d|hims6 y=
.-
C. V =.'-vo
o
x+
C. m=I.
I ..
l2m- - I)tanx
Ian2 x+tan-rr+1
1,
m<- J' noac
^1U ltn <---.
rl2
nghich bi6n tr€n khodng [0,+] tu"\ 4)
D.V=
6
', 
l r J,glac co olen ttcn Dang
D. m=4.
c6 dring mQt tiQm cAn ngang ldL
D. 0< m<1.
o' 16
x-3
^lmr'? + 4
fnI m=UB. l ,.
LM= T
B.
1
m> t-,taNL
D.
slMade138
Ciu 48: M6t ngon hAi dang d4t t4i vt tri A c6ch bo bi€n mQt
n r/r \ r \ 1'^klroang AB:51k ,).Trdn bo bi€n co mot cdi kho o vi tri C
circh B m6t khodng 7(km). Nguo'i canh hdi dang c6 th€ chdo
.t ..: ^ , , ,.;,dd tu I ddn didm ,V tr€n bo bien voi vdn t6c 4km / h roi di b0
d6n C v6i vAn t6c 6krn I h (Hinh 2). De nguoi d6 dtSn kho
' 
i..' 
'nhanh nhat thi vi tri cira M c6ch C mOt khoing lir
Ciu 49: Chi Chdu vay 30 triQu d6ng cira ng6n hdng dri mua xe mdy yd phdi trd g6p trong vdng 2 n6m v6i
i., ^^, x..,,' .r' -^, ^i^,,l-, t: 4.:i---i i--r-r:rral suar t,^/.-/o mor m6ng. Hdng th6ng Chi ChAu phAi trA mQi sd ti€n co dinh la bao nhiOu d6 sau 3 nam h6t
no? (ldm tron d€n dcrn vi d6ng)
^.3Ji(hn)
c. sJl(km)
A.1446062 d6ng.
A. a =L.
6
B. a =L.
5
B. 7 
-2nE (km).
D. 2Ji (hi
8.1456062 ddng. C. 1466062 ddng. D. 1476062 ddng.
Ciu 50: Cho hinh chop tf gi6c dAu c6 mdt b€n ld c6c tam gi6c cAn vdi g6c o dinh bdng a ld g6c nhon.
Bi6t t6m cta mdt cAu ngoai ti€p hinh chop c6ch d€u t6t cA" ctrc m5t cira hinh ch6p. Gi6 tri cta a lit
TT
C. a =!-.
4
rrA.
-rt-ct" -------------
17
D. a ='J-.aJ
6lMada138